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Edelbrock Performance Tech Discussion

Edelbrock Performance Tech Discussion

Optimizing your car's performance requires more than just throwing a bunch of parts under the hood. Understanding the relationship between various systems and the mathematical computations necessary to determine which parts will give you the performance you want is key to improved performance in today's factory-tuned cars. Use the info in this section to help you select the correct parts for your application. If you have any questions, give a call to our toll-free Factory Tech Line: 1-800-416-8628.

Emissions Guide Warranty Info EFI Tech Forum Edelbrock Quick Support


POWER PACKAGE PERFORMANCE LEVELS (5)

PerformerTorker IIPerformer RPM / RPM Air-GapVictor Jr.Super Victor +
Compression Ratio8.5:19.5:19.5:112.5:112.5+:1
Cylinder HeadPerformer or StockPerformer RPMPerformer RPMVictor Jr.CNC Victor
CamshaftHydraulicHydraulicHydraulicMechanical/RollerMechanical/Roller
Intake (DU @ .050)200° - 220°220° - 230°230° - 240°250°+270°+
Exhaust (DU @ .050)210° - 230°230° - 240°240° - 250°260°+276°+
Valve Lift (small-block)0.400" - 0.450"0.450" - 0.500"0.500" - 0.550"0.600" - 0.650"0.650"+
Operating Band (rpm)Idle - 55002500 - 65001500 - 65003500 - 75004500 - 8500+
Manifold Type2 Plane, Low Rise1 Plane, Low Rise2 Plane, Hi-Rise1 Plane, Hi-Rise1 Plane, Hi-Rise
Volumetric Efficiency75 - 90%90 - 100%95 - 105%105 - 115%110 - 122%
Peak Torque (rpm)38004500450053006300
Peak HP (rpm)52006000600070008000+
Pkg. Goal (hp/Cu. In.)0.7 - 0.90.8 - 1.10.9 - 1.31.2 - 1.71.6 - 2.0

MILE PER HOUR AND REVOLUTIONS PER MINUTE

First find the vehicle speed, MPH and the consequent engine RPM operating range:

FORMULA FOR MPH
MPH = TIRE RADIUS ÷ 168 x ENGINE RPM ÷ GEAR RATIO

Example: What MPH at 6500 RPM with a 4.9 rear axle and 14 inch radius tire in 4th (1:1) gear?
MPH = 14 ÷ 168 x 6500 ÷ 4.90 ÷ 1 = 111 MPH
Example: In 3rd gear (1.34)?
MPH = 14 ÷ 168 x 6500 ÷ 4.90 ÷ 1.34 = 83 MPH
Note: Tire Radius is distance, in inches, from center of wheel to the top of the tire.
Note: Gear Ratio is Rear Axle ratio divided by Transmission Gear ratio.

FORMULA FOR RPM
RPM = 168 x GEAR RATIO x MPH ÷ TIRE RADIUS

Example: Using the first example, what will be the RPM after shift from 3rd to 4th gear at 83 MPH? RPM = 168 x 4.90 x 83 ÷ 14 = 4880 RPM

FORMULA FOR GEAR RATIO (GR)
GEAR RATIO = TIRE RADIUS x RPM ÷ 168 ÷ MPH

Example: Using the first example, what Gear Ratio is required for 120 MPH at 6500 RPM? GR = 14 x 6500 ÷ 168 ÷ 120 = 4.51

FORMULA FOR TIRE RADIUS
TIRE RADIUS = 168 x MPH x GEAR RATIO ÷ RPM

Example: Using the first example, what tire radius for 110 MPH but at 6000 RPM with a 4.11 gear? Tire Radius = 168 x 110 x 4.11 ÷ 6000 Tire Radius = 12.7 inches Note: Approximately a 25" diameter tire. Remember that the tire radius will be less during hard acceleration than when the vehicle is standing still. Also, radius will be greater at high speed due to tire expansion from centrifugal force.

DISPLACEMENT, VOLUMETRIC (VE) EFFICIENCY, AND CFM

FORMULA FOR VOLUMETRIC (VE) EFFICIENCY
VE = (CFM X 3456) ÷ (CID X RPM)

If VE (volumetric efficiency) is less than 1 (or 100%) the amount and quality of charge in the cylinder is reduced so less torque is produced. VE above 100% is a supercharging effect and more torque is produced.

Power LevelStockPerformerTorker IIPerf. RPMVictor Jr.Super Victor +
Peak VE%60-8075-9090-10095-105105-115110-122
FORMULA FOR CID (cubic inch displacement)
CID = NUMBER OF CYLINDERS x SWEPT VOLUME

Note: CID = N x 0.7854 x bore x bore x stroke (all in inches)
Example: What is CID of a V8 with a “30 over”, 4 inch bore and 3.48 inch stroke?
CID = 8 x 0.7854 x 4.030 x 4.030 x 3.48
CID = 355 cu. inches

FORMULA FOR CFM
CFM = CUBIC FEET PER MINUTE

A measure of air flow into and out of an engine (CFM = CID x RPM x VE ÷ 3456).
Example: What CFM is consumed by a 355 CID engine at 4500 RPM if VE = 105% (1.05)?
CFM = 355 x 4500 x 1.05 ÷ 3456
CFM = 485 Example: What CFM by the same engine at 6400 RPM if VE has fallen to 95% (0.9)?
CFM = 355 x 6400 x 0.95 ÷ 3456

CFM = 625

TO CONVERT C.I.D. TO CC'S
C.I.D. = CC ÷ 16.39

Example: What is the cubic-inch displacement of a 5000 cc engine?
C.I.D. = 5000 ÷ 16.39
C.I.D. = 305

TO CONVERT CC'S TO C.I.D.
CC = C.I.D. X 16.39

Note: cc = cubic centimeter, 1,000 cc = 1 liter
Example: What are the cc’s of a 350 C.I.D. engine?
cc’s = 350 x 16.39
cc’s = 5736.5

Please Note: The above equations and rules apply only to four-cycle engines. The equations have been simplified for ease of understanding. Answers will be approximate but generally will be close enough for use as a guideline.

COMPRESSION RATIO

FORMULA FOR COMPRESSION RATIO (CR)
CR = CYL. VOLUME @ BDC ÷ CYLINDER VOLUME @ TDC

CV = CLEARANCE VOLUME
CR = (CV + SWEPT VOLUME) ÷ CV
CR = 1+ SWEPT VOLUME ÷ CV
CR = 1+ (SWEPT VOLUME ÷ VOL @ TDC)
CR = 1+ (0.7854 x BORE x BORE x STROKE) ÷ (CCV + HGV + PDV)
CCV = Combustion Chamber Volume, in cubic inches
Note: if volume is given in cc’s then ÷ 16.4 to get cubic inches.
HGV = Head Gasket Volume, in cubic inches,
HGV = Head gasket compressed thickness x 0.7854 x bore x bore
PDV = (Piston Deck Volume) + (Piston Dome Effective Volume)
PDV = (0.7854 x bore x bore x deck to piston distance) +
(volume of piston depressions - volume of piston bumps)
CV = CCV + HCV + PDV
Example: What is CR of the engine in #9 if heads have 72 cc chamber, head gasket is compressed to 0.040 inch and flat top pistons give 0.025 deck clearance at TDC?

Please Note: The above equations and rules apply only to four-cycle engines. The equations have been simplified for ease of understanding. Answers will be approximate but generally will be close enough for use as a guideline.

EFI SYSTEM FORMULAS

FORMULA FOR INJECTOR SIZE SELECTION
LBS/HR = ((BSFC ÷ # CYL'S) X HP) ÷ PEAK INJECTION DURATION

Example: What size injectors should you use for a Super Victor EFI 600 hp 350 cid Chevy?
Lbs/Hr = ((0.50 ÷ 8) x 600) ÷ 0.85
Lbs/Hr = 37.5 ÷ .85
Lbs/Hr = 44

FLOW RATE CHANGE BY PRESSURE REGULATOR CHANGE
F2 = (√P2 ÷ √P1) x F1

F2 = New flow rate (lbs/hour or cc/min)
F1 = Old flow rate (lbs/hr or cc/min)
P2 = New Pressure
P1 = Old Pressure

An adjustable fuel pressure regulator allows you to change the amount of fuel delivered per unit time from the injector. Any changes affect the fuel curve globally, so re-mapping the idle and light load conditions is usually necessary. The mass flow is proportional to the square root of the pressure ratio:
Example: You have a 28 Lb/hr (@45 psi) injector. How much will it flow at 60 psi?
F2 = (√60 ÷√45) x 28 Lbs/hr
F2 = (7.746 ÷ 6.708) x 28 Lbs/hr
F2 = 32.3 Lbs/hr

MAXIMUM HORSEPOWER SUPPORTED BY A GIVEN INJECTOR
HP = [(INJECTOR SIZE (LB/HR) X DUTY CYCLE) ÷ BSFC] X (# OF INJECTORS)

Example: How much power can be supported by eight 28 Lb/hr injectors?
HP = [(28 Lb/hr x 0.90) Ö 0.50 Lb/HP hr] x 8
HP = 50.4 HP x 8
HP = 403

TO CONVERT CC/MIN TO LBS/HR
DIVIDE CC/MIN BY 10.5

Please Note: The above equations and rules apply only to four-cycle engines. The equations have been simplified for ease of understanding. Answers will be approximate but generally will be close enough for use as a guideline.

PRESSURE AND FLOW

PRESSURE CONVERSION FACTORS
=KpaAtmIn. HgIn. H2OPSI
1.0 Kpa=1.0.00987.2954.018.145
1.0 Atm=101.31.029.92407.114.7
1.0 in Hg=3.386.033421.013.61.491
1.0 in H20=.2489.02456.073491.0.0361
1.0 PSI =6.8948.068052.03627.71.0

Example: You have 15 in Hg (inches of Mercury) at idle. How much is this in Kpa?
Kpa = 3.386 x 15
Kpa = 50.8

FLOW BENCH CONVERSION FACTOR
CFM = CFM x √(28 ÷ P)

Typically flow bench values are given for a pressure drop of 28 in H2O. To convert flow figures from a different pressure drop to 28 in H2O use the formula above.
Example: You have flow figures of 152 cfm at 10 in H2O. What if the same head was flowed at 28 in H2O?
CFM = 152 x √(28÷10)
CFM = 254 cfm

Please Note: The above equations and rules apply only to four-cycle engines. The equations have been simplified for ease of understanding. Answers will be approximate but generally will be close enough for use as a guideline.

FUEL SYSTEM REQUIREMENTS

BRAKE SPECIFIC FUEL CONSUMPTION

Brake Specific Fuel Consumption is the ratio of fuel consumed (in lbs. per hour) to horsepower produced. This ratio is a direct indicator of how efficiently the engine converts fuel into power. Most factory gasoline type engines run approximately a .50 to .55 Brake Specific Fuel consumption (BSFC) range while a highly efficient normally aspirated race engine operates at approximately a .40-.45 BSFC.

  • Most common turbocharged or supercharged engine configurations run in the .55 to .60 BSFC range
  • For Methanol powered applications the BSFC is doubled (i.e. turbo/methanol: 1.10-1.20)

These factors should be considered when sizing & selecting injectors for your particular application.

LBS/HR = HP X BSFC

Generally BSFC = 0.50.
Example: How much fuel flow will you need to feed your new 440 hp E-Tec EFI crate engine?
Lbs/hr = 440 x 0.50
Lbs/hr = 220

GPH = LBS/HR ÷ 6.0

Example: What is the GPH for the 440 hp crate engine?
Lbs/hr = 220 ÷ 6
Gals/hr = 37

Please Note: The above equations and rules apply only to four-cycle engines. The equations have been simplified for ease of understanding. Answers will be approximate but generally will be close enough for use as a guideline.

CFM RULES

CFM and Carburetors:

Carburetors are rated by CFM (cubic feet per minute) capacity. 4V carburetors are rated at 1.5 inches (Hg) of pressure drop (manifold vacuum) and 2V carburetors at 3 inches (Hg). Rule: For maximum performance, select a carburetor that is rated higher than the engine CFM requirement. Use 110% to 130% higher on single-plane manifolds. Example: If the engine needs 590 CFM, select a carburetor rated in the range of 650 to 770 CFM for a single-plane manifold. A 750 would be right. An 850 probably would cause driveability problems at lower RPM. A 1050 probably would cause actual loss of HP below 4500 RPM. For dual-plane manifolds use 120% to 150% higher.

CFM and Manifolds:

Manifolds must be sized to match the application. Because manifolds are made for specific engines, select manifolds based on the RPM range.

CFM and Camshafts:

With the proper carburetor and manifold it is possible to select a cam that loses 5% to 15% of the potential HP. These losses come from the wrong lift and duration which try to create air flow that does not match the air flow characteristics of the carburetor, manifold, head and exhaust so volumetric efficiency is reduced. An increase in camshaft lobe duration of 10 degrees will move the HP peak up 500 RPM but watch out; it may lose too much HP at lower RPM.

CFM and Cylinder Heads:

Cylinder heads are usually the limiting component in the whole air flow chain. That is why installing only a large carburetor or a long cam in a stock engine does not work. When it is not possible to replace the cylinder heads because of cost, a better matching carburetor, manifold, cam and exhaust can increase HP of most stock engines by 10 to 15 points. To break 100% Volumetric Efficiency, however, better cylinder heads or OEM “HO” level engines are usually needed.

CFM and Exhaust:

An engine must exhaust burned gases before it can intake the next fresh charge. Cast iron, log style manifolds hamper the exhaust process. Tube style exhaust systems are preferred. But headers are often too big; especially for Performer and Performer RPM levels. Improving an engine’s Volumetric Efficiency depends on high exhaust gas velocity to scavenge the cylinder. This will not happen if the exhaust valve dumps into a big header pipe. On the newer computer controlled vehicles it is also important to ensure that all emissions control devices, and especially the O2 sensor, still work as intended.

CFM and Engine Control:

Spark timing must be matched to Volumetric Efficiency because VE indicates the quantity of charge in each cylinder on each stroke of the engine. Different engine families require distinctly different spark advance profiles. And even engines of equal CID but different CR require their own unique spark advance profiles. Rule: Expect 0.1% to 0.5% loss in Torque for each 1 degree error in spark timing advanced or retarded from best timing. Also, detonation will occur with spark advanced only 3 degrees to 5 degrees over best timing and detonation will cause 1% to 10% torque loss, immediately, and engine damage if allowed to persist.

E-FORCE BOOST MEASUREMENT

Installing A Boost Gauge Or Pressure Tranducer

1. The TMAP sensor mounted on top of the manifold at the rear of the driver's side, outputs a 0-5 volt signal through pins 1 & 2 (pin 1 is signal & pin 2 is signal return,) that can be converted to an absolute pressure reading using the below calibration curve. Use of this signal requires an ambient pressure correction for calculating boost pressure.

VoltagePressure
0.622.70
0.803.69
1.095.70
1.407.69
1.719.70
2.1712.70
2.4614.70
2.7016.21
2.9417.70
3.2519.71
3.5521.70
3.8423.71
4.1525.70
4.4627.70
4.7629.70

2. The second option is to utilize the pressure port at the rear of the passenger side intake runner flange. Your supercharger has been pre-drilled and tapped for a 1/8" NPT fitting. There is currently a plug sealing the hole, which can be removed, and replaced with a fitting to adapt to your sensor.

CAUTION: Never cut into the vacuum lines leading to the fuel rail pressure sensor and bypass actuator, on the driver's side of the manifold, for the purpose of tapping in a boost gauge. Interruption of the vacuum signal to the fuel rail pressure sensor can affect the fuel pressure reading to the PCM, which can result in engine failure! Furthermore, this port reads pressure before the intercooler, and therefore is before the inherent intercooler pressure drop. Readings from this port will always be approx. 20% higher then what the engine actually sees.

If measured properly on an otherwise stock 4.6L Mustang GT, your boost readings, utilizing an electronic transducer or MAP sensor, on a dyno, should be comparable to this boost curve, shown below, collected from a recent dyno test here at Edelbrock. If you install a mechanical boost gauge in your vehicle, you will see a steady 5 PSI on the gauge during full throttle acceleration on the street.

RPMBoost
26005.092
30005.733
35005.541
38005.637
40005.733
43005.637
45005.701
46005.829
47005.765
48005.509
49005.701
50005.798
RPMBoost
51005.862
52006.085
53006.278
54006.278
55006.342
56006.502
57006.663
58006.950
59006.950
60007.272
61007.336
62007.559

E-FORCE TMAP INFORMATION FOR FORD & BOSCH SENSORS

If you are using a custom calibration for your GM based E-Force application you will need the following TMAP information in order for the Manifold Absolute Pressure and Intake Air Temperature parameters to read correctly.

To help determine which sensor you have you can look at the serial number.

If your superchargers serial number is between 1 and 1611 your system will have the Ford TMAP, unless you have a Z06, all Z06 applications use the Bosch TMAP regardless of what the serial number is. The Ford TMAP will be attached to the supercharger housing with 2 bolts.

If your superchargers serial number is 1612 or greater your system will have the Bosch TMAP. The Bosch TMAP will be attached to the supercharger housing with 1 bolt.

Ford TMAP Sensor Information

For E-Force Superchargers with Serial number 0 - 1611 (other than Z06, all Z06 applications use the Bosch TMAP)

NOTE: If you have a 2005 LS2 the offset cannot be below 0, so just use 0 and it will be fairly close.

MAP Sensor Linear: 223.43 kpa

MAP Sensor Offset: -7.88 kpa

IAT Sensor Curve
ResistanceTemperature C°
563150
715140
918130
1191120
1564110
2080100
280490
327385
383780
451575
533770
633565
755660
905655
1090850
1321645
1609240
1969635
2423930
3000025
3735220
4679715
5901610
749405
958510
123485-5
160313-10
209816-15
276959-20
368896-25
496051-30
673787-35
925021-40
IAT Sensor Curve 2
ResistanceTemperature F°
563302
715284
918266
1191248
1564230
2080212
2804194
3273185
3837176
4515167
5337158
6335149
7556140
9056131
10908122
13216113
16092104
1969695
2423986
3000077
3735268
4679759
5901650
7494041
9585132
12348523
16031314
2098165
276959-4
368896-13
496051-22
673787-31
925021-40
Bosch TMAP sensor information

For all Z06 applications and GM E-Force Superchargers with Serial number 1612 and greater

NOTE: If you have a 2005 LS2 it will limit the Linear to 255.9 and the offset can't be below 0 so just use those values and it will be fairly close.

MAP Sensor Linear: 268.9 kpa

MAP Sensor Offset: -1.65 kpa

NOTE: The stock IAT values should be fairly close, if they are not you can use the values below.

IAT Sensor Curve
ResistanceTemperature C°
58150
72140
90130
113120
144110
186100
24390
32180
43170
58760
81350
114840
165330
200025
243320
366310
56520
8969-10
14700-20
24710-30
43320-40
43321-40
43322-40
43323-40
43324-40
43325-40
43326-40
43327-40
43328-40
43329-40
43330-40
43331-40
43332-40
IAT Sensor Curve 2
ResistanceTemperature F°
47302
101284
133266
178248
980230
1148212
1349194
1592185
1884176
2144167
2445158
2795149
3202140
3511131
3678122
3854113
4039104
423595
444186
465977
488868
513159
538750
565841
624732
690523
764314
84705
9906-4
12261-13
16120-22
28583-31
100866-40

E-FORCE THROTTLE BODY COMPARISON

Edelbrock E-Force (85mm) vs. Ford Mustang GT twin (55mm) and GT 500 twin (62mm)

Stock twin 55mm bore with 10mm shaft = 5.66 sq. in. total area

GT500 twin 60mm bore with 10mm shaft = 6.91 sq. in. total area

Edelbrock single 85mm bore with 8.8mm shaft = 7.64 sq. In. total area

In addition, area being equal, a single bore will always flow better than a twin bore because there is less bounding surface area to interrupt the flow. Also, both the stock GT throttle body and the GT500 throttle body have an as cast surface leading into the bores, where the Edelbrock unit is machined through for less wall friction. Last, the inlet is port matched to the throttle body for a perfect matching transition.